1、打开Python开发工具IDEL，新建‘浅拷贝.py’文件，编写代码如下：list = []for i in range(10): list.append({'mykey':i})print (list)
2、F5运行程序，打印出list列表内容：[{&#补朱锚卦39;mykey': 0}, {'myke烤恤鹇灭y': 1}, {'mykey': 2}, {'mykey': 3}, {'mykey': 4}, {'mykey': 5}, {'mykey': 6}, {'mykey': 7}, {'mykey': 8}, {'mykey': 9}
3、在‘浅拷贝.py’文件，继续编写代码如下;list = []for i in range(10): list.append({'mykey':i})print (list)list1 = []dicta = {'mykey':0}for i in range(10): dicta['mykey']=i list1.append(dicta)print (list1)
4、F5运行程序，打印出list列表内容：[{&#补朱锚卦39;mykey': 0}, {'myke烤恤鹇灭y': 1}, {'mykey': 2}, {'mykey': 3}, {'mykey': 4}, {'mykey': 5}, {'mykey': 6}, {'mykey': 7}, {'mykey': 8}, {'mykey': 9}打印出list1列表内容:[{'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}, {'mykey': 9}]
5、这是因为浅拷贝，列表中每项都存的只是字典的引用，指向同一地址，而每次dicta['mykey']重新赋值列表中每项都随之改变。
6、清空‘浅拷贝.py’内容，重新写代码如下：import copyqts = ['y','z'] list1 = ['x',qts]list = copy.copy(list1)print (list1)print (list)list1.append('6')print (list1)print (list)qts[0]='change'print (list1)print (list)
7、F5运行程序，打印出几次列表内容：['垓矗梅吒x', ['y', 'z']]['x', [媪青怍牙'y', 'z']]['x', ['y', 'z'], '6']['x', ['y', 'z']]['x', ['change', 'z'], '6']['x', ['change', 'z']]
8、第一次list = copy.copy(list1)浅拷贝后，list和list1指向了相同的地址，之后list1.append('6')这次list1增加了一个字符串的指向，与list无关，但是当他们共同指向的嵌套列表qts改变内容后，两个列表都会受到影响。
