1、解法二：思路：利用不定积分的分部积分方法求得： I=∫x^2*xdx/√(1-x^2) =-(1/2)∫x^2d(1-x^2)/√(1-x^2) =-∫x^2d√(1-x^2) =-x^2√(1-x^2)+ ∫√(1-x^2)dx^2 =-x^2√(1-x^2)-∫√(1-x^2)d(1-x^2) =-x^2√(1-x^2)-(2/3)√(1-x^2)^3+c
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时间：2024-10-25 15:44:12
1、解法二：思路：利用不定积分的分部积分方法求得： I=∫x^2*xdx/√(1-x^2) =-(1/2)∫x^2d(1-x^2)/√(1-x^2) =-∫x^2d√(1-x^2) =-x^2√(1-x^2)+ ∫√(1-x^2)dx^2 =-x^2√(1-x^2)-∫√(1-x^2)d(1-x^2) =-x^2√(1-x^2)-(2/3)√(1-x^2)^3+c